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Direction : The questions 60 and 61 are based on following paragraph : An X-ray tube operated at a D.C, voltage of 40 kV produces heat at the target at the rate of 720 W. If 0.5% of the energy of the incident electron is converted into X-ray radiation, then (sp. charge is 1.8xx10^(11)C//kg). Number of electrons striking the target per/sec is

Answer»

`2.2xx10^(-17)`
`1.1xx10^(17)`
`2.2xx10^(18)`
`71.1xx10^(18)`

Solution :No. of electrons produced/ sec `N=(I)/(e)`
No heat produced/sec. `=(955)/(100)IV`
`=0.955xIXx40,000` `:.I=(720)/(0.955xx40,000)=0.018A`
Then `n=(I)/(e)=(0.018)/(1.65xx10^(-19))=1.1xx10^(7)`


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