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Directions for Questions 56 and 57: In each question, there is a table having 3 columns and 4 rows. Based on the table, there are 3 questions. Each question has 4 options (a), (b), (c) and (d), ONLY ONE of these four options is correct. Two charges of opposite sign and equal magnitude Q = 2.0 C are held 2.0 m apart. And there is a point Pat 4.0 cm from +Q charge. In the given table there are four values each of electric field (Column I), potential difference each of electric field (Column I), potential difference {:("Column I","Column II", "Column III"),((I) E=1.27 xx 10^(9) V//m,(i) V=1.5 xx 10^(9) V,(J) (##MST_AG_JEE_MA_PHY_V02_C24_E03_059_Q01.png" width="80%"> The combination for maximum electric field is |
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Answer» (I) (II) (M) |
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