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Directive gain of antenna when radiation intensity is 5W/Steradian and radiated power 5W is ____(a) 4π(b) 1/4π(c) 25(d) 1I have been asked this question by my school principal while I was bunking the class.My question comes from Directive Gain topic in division Antenna Parameters of Antennas

Answer»

The CORRECT option is (a) 4π

To ELABORATE: Given Ud(θ,∅) = 5W/steradian , Pr=5W

Directive gain \(G_d=\frac{P_{d(\theta,\emptyset)^{r^2}}}{P_r/4\pi} = \frac{U_{d(\theta,\emptyset)}}{P_r/4\pi}=4\pi\)



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