InterviewSolution
Correct choice is (C) 0≤η≤1Explanation: RADIATION efficiency ηr=\(\FRAC{R_r}{R_r+R_l}\) Rr+Rl>Rr So \(\frac{R_r}{R_r+R_l}\) < 1 and If Rl=0 then ηr=1Therefore, the value of efficiency lies in the range 0 to 1.
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