InterviewSolution
Saved Bookmarks
| 1. |
Discuss the intensity of transmitted light when a polaroid sheet is rotated between two crossed polaroids ? |
|
Answer» <P> Solution :Let `I_(0)` be the intensity of polarised light after passing through the first polariser `P_1` Then the intensity of light after passing through second polariser `P_2` will be `I =I_(0)cos^(2)e,` where `theta` is the angle between pass axes of `P_1 and P_2.` SINCE `P_1 and P_3` are crossed the angle between the pass axes of P, and `P_3` will be `(pi//2 -theta)`. Hence the intensityof light EMERGING from `P_3` will be`I=I_(0)cos^T(2)thetacos^(2)((pi)/(2)-theta)` `=I_(0)cos^(2) thetasin^(2)theta=(I_(0)//4)SIN^(2)2theta` Therefore, the transmitted intensity will be maximum when `theta= lambda//4.` |
|