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Discuss the intensity of transmitted light when a polaroid sheet is rotated between two crossed polaroids ?

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Solution :Let `I_(0)` be the intensity of polarised light after passing through the first polariser `P_1` Then the intensity of light after passing through second polariser `P_2` will be `I =I_(0)cos^(2)e,` where `theta` is the angle between pass axes of `P_1 and P_2.` SINCE `P_1 and P_3` are crossed the angle between the pass axes of P, and `P_3` will be `(pi//2 -theta)`. Hence the intensityof light EMERGING from `P_3` will be
`I=I_(0)cos^T(2)thetacos^(2)((pi)/(2)-theta)`
`=I_(0)cos^(2) thetasin^(2)theta=(I_(0)//4)SIN^(2)2theta`
Therefore, the transmitted intensity will be maximum when `theta= lambda//4.`


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