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Discuss the intensity of transmitted light when a polaroid sheet is rotated between two crossed polaroids. |
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Answer» Solution :Let `I_(0)` be the intensity of polarised light after passing through the first polariser`P_(1)`. Then the intensity of light after passing through second polariser `P_(2)` will be `I=I_(0)cos^(2)theta`, where `theta` is the angle between pass AXES of `P_(1)` and `P_(2)`. SInce `P_(1)` and `P_(3)` are crossed the angle between the pass axes of `P_(2)` and `P_(3)` will be`((pi)/2-theta)`.HENCE the intensity of light emerging from `P_(3)` will be `I=I_(0)cos^(2)theta cos^(2)((pi)/2-theta)=I_(0)cos^(2) SIN^(2) theta=((I_(0))/4)sin^(2) 2 theta` Therefore the transmitted intensity will be maximum when `theta=(pi)/4` |
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