Disintegration constant of a radioactive material is `lambda`:A. Its half life equal to `(log_(e)2)/(lambda)`B. It mean life equals to `(1)/(lambda)`C. At time equal to mean life, `63%` of the Initial radioactive material is left undecayedD. After `3-` half 1/3 rd of the initial radioactive material is left undecayed.

Disintegration constant of a radioactive material is `lambda`:A. Its h

1.	Disintegration constant of a radioactive material is `lambda`:A. Its half life equal to `(log_(e)2)/(lambda)`B. It mean life equals to `(1)/(lambda)`C. At time equal to mean life, `63%` of the Initial radioactive material is left undecayedD. After `3-` half 1/3 rd of the initial radioactive material is left undecayed.
Answer» Correct Answer - A::B `N = N_(0)e^(-lambdat) rArr (N_(0))/(10) = N_(0)e^(-lambdaT_(1//2))` `rArr T_(1//2) = (log_(e)2)/(lambda) rArr T_(mean) = (1)/(lambda)`

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