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Displacement-time equation of a particle executing SHM is `x=A sin (omega t+(pi)/6)` Time taken by the particle to go directly from `x=-A/2"to"x=+A/2`A. `(pi)/(3omega)`B. `(pi)/(2omega)`C. `(pi)/(omega)`D. `(pi)/(omega)`

Answer» Correct Answer - A


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