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Displacementof the hydroxy1 group of alcohol can take place with variety of reagents. One such reaction is HBr+CH_(3) CH_(2)OH to CH_(3)CH_(2)Br+H_(2)O The above reaction has a two-step mechanism. (a) CH_(3)CH_(2)OH+H^(+)overset(k_(eq))(hArr) CH_(3)CH_(2)OH_(2)^(+) (b) CH_(3)CH_(2)OH_(2)^(+)+Br^(-) overset(k_(2))(to)CH_(3)CH_(2)Br+H_(2)O The slow and fast can be identified by the fact that rate of displacement of hydroxyl by halide ions depends on the type of halide ion . Calculate the rate of the formation of Ethyl Bromide when concentration of alcohol is 0.5 M and HBr is 10^(-1) M. Assume complete dissociation of HBr. Express your answer in terms of 10^(-6) M//sec. ["Given" : K_(eq) = 4M ^(-1)"and" K_(2) = 5xx10^(-2) M^(-1) sec^(-1)]

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