1.

Dissociation constant of NH_4OH is 1.8 times 10^-5 the hydrolysis constant of NH_4Cl would be …….

Answer»

`1.8 TIMES 10^-19`
`5.55 times 10^-10`
`5.55 times 10^-5`
`1.80 times 10^-5`

SOLUTION :`K_h=K_w/K_b=(1.8 times10^-14)/(1.8 times10^-5)=0.55 times10^-9=5.5 times10^-10`


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