Dissociation equilibrium constant of HI is 2.06xx10^(-2) at 458^(@)C. – InterviewSolution

1.	Dissociation equilibrium constant of HI is 2.06xx10^(-2) at 458^(@)C. At equilibrium, concentrations of HI and I_(2) are 0.36M and 0.15M respectively. What is the equilibrium concentration of H_(2) at 458^(@)C.
Answer» ANSWER :`[H_(2)]=1.78xx10^(-2)M`

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