1.

Dissolving 120 g of urca (mol . Wi 60) in 1000 gof water gave a solution of density 1.15 g/mL the molarity of the solution is

Answer»

`1.78` M
`2.00`M
`2.05` M
`2.22` M

SOLUTION :NUBER of MOLES of urea `= (120)/(60)=2`
Total mass of solution `=1000+120=1120g `
Total VOLUME of solution (in L) `= ("Mass)/("Density") =(1120)/(1.15xx10^(3))=(112)/(115)l.`
MOLARITY of the solution `= ("Number of moles")/("Volume of solution litre")=(2xx115)/(112) =2.05 mol L ^(-1)`


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