1.

Dissolving 120 g of urea (molecular mass = 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is :

Answer»

`1.78 M`
`2.00 M`
`2.05 M`
`2.22 M`

Solution :Total MASS of solution
=1000+120=120=1120 g
Total VOLUME of solution
`="Mass"/"Density"=((1120g))/((1.15"g mL"^(-1)))`
=973.91.= mL
`"Molarity(M)"=("GRAM moles of solute")/("Volume of solution in liters")`
`=((120g//60"g MOL"^(-1)))/((973.91//1000L))=2.05 "mol L"^(-1)`
=2.05 M.


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