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Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:A. `1.78 M`B. `1.02 M`C. `2.05 M`D. `0.50 M` |
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Answer» Correct Answer - C Mass of solute =`120 g` Molecular mass of solute `=60 u` Mass of solvent `=1000 g` Density of solution `=1.15 g//mL` Total mass of solution `=1000+120=1120 g` `"Volume of solution"=("Mass")/("Density")=(1120)/(1.15)mL` `"Molarity"=(("Mass of solute")/("Molecular mass of solute"))/("Volume of solution")xx1000` `=(120//60)/(1120//1.15)xx1000` `=(2xx1000xx1.15)/(1120)=2.05 M` |
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