1.

Distance between two image formed by upper and lower part of the point object placed at 30 cm from given lens is (60+x)cm, then the value of x is

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SOLUTION :`F/(f_(L))=(3/2-1)(1/20-1/20)`
`implies f_(L)=20CM`
`1/f=1/(-10)-2/20=-1/5`
`1/v+1/(-30)=1/(-5)implies1/v=1/30-1/5`
for lens `1/v-1/(-30)=1/20`


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