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Distance between two points on paper is They are observed such that view line observer is perpendicular to them. Diameter lens of an eye of an observer is 2 mm. Fo which minimum value of d both points will h observed ? |
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Answer» `1.25 cm` where d = diameter of lens of eye If DISTANCE between two points is Y and distance from eye is D. then `theta=(y)/(D)` `(y)/(D)=(lambda)/(d) rArr Y=(lambdaD)/(y) ""...(1)` `Y=(5xx10^(-7)xx50)/(2XX10^(-3))=12.5xx10^(-3)m=12.5 cm` |
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