1.

Distance between two points on paper is They are observed such that view line observer is perpendicular to them. Diameter lens of an eye of an observer is 2 mm. Fo which minimum value of d both points will h observed ?

Answer»

`1.25 cm`
`12.5 cm`
`1.25 cm`
`2.5 mm`

Solution :Resolution of eye `THETA=(LAMBDA)/(d)`
where d = diameter of lens of eye
If DISTANCE between two points is Y and distance from eye is D. then `theta=(y)/(D)`
`(y)/(D)=(lambda)/(d) rArr Y=(lambdaD)/(y) ""...(1)`
`Y=(5xx10^(-7)xx50)/(2XX10^(-3))=12.5xx10^(-3)m=12.5 cm`


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