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Distance betweentwo parallel planes `2x""+""y""+""2z""=""8`and `4x""+""2y""+""4z""+""5""=""0`is(1) `5/2`(2) `7/2`(3) `9/2`(4) `3/2` |
Answer» given planes are : `(2x+y+2z=8)xx 2 = 4x + 2y + 4z = 16` `4x+2y + 4z = -5` distance`= (|16 - (-5)|)/sqrt((4)^2 + (2)^2 + (4)^2)` `= 21/sqrt36 = 21/6 = 7/2` Answer option 2 is correct |
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