1.

Distance of a point (2,5) from the line 2x-y-4=0 measured parallel to the line 3x-4y + 8 = 0 is :

Answer» (y-5)=3/4(x-2)
4y-20=3x-6
4y-3x-14=0-(1)
Given 2x-y-4=0-(2)
From equation 1 and 2
4(2x-4)-3-14=0
8x-3x-30=0
x=6
y=8
A(6,8)
AB=`sqrt((6-2)^2+(8-5)^2)`
`=sqrt(4^2+3^2)`
=5 Units.


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