divide 150 into three parts such that the second number is five-sixths

1.	divide 150 into three parts such that the second number is five-sixths the first and the third number is fourth-fifths the second
Answer» Answer: 60, 50, 40 Step-by-step explanation: LET the NUMBERS be x, y, z 5x/6 = y 4y/5 = z ⇒ 4/5 × 5x/6 = z x + y + z = 150 x + 5/6x + 4/5 × 5/6x = 150 $\frac{6x + 5x + 4x}{6}$ = 150 $\frac{15x}{6}$ = 150 x = 60 y = $\frac{560}{6}$ = 50 z = 150 - 60 - 50 = 40*

divide 150 into three parts such that the second number is five-sixths the first and the third number is fourth-fifths the second

Answer»

Answer:

60, 50, 40

Step-by-step explanation:

LET the NUMBERS be x, y, z

5x/6 = y

4y/5 = z ⇒ 4/5 × 5x/6 = z

x + y + z = 150

x + 5/6x + 4/5 × 5/6x = 150

$\frac{6x + 5x + 4x}{6}$ = 150

$\frac{15x}{6}$ = 150

x = 60

y = $\frac{5*60}{6}$ = 50

z = 150 - 60 - 50 = 40