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Divide 18x^2 by 6x pls help algebra question |
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Answer» Equation at the end of step 1 (2•32x2) - 6x = 0 STEP2:STEP3:Pulling out like terms 3.1 Pull out like factors : 18x2 - 6x = 6x • (3x - 1) Equation at the end of step3: 6x • (3x - 1) = 0 STEP4:Theory - Roots of a product 4.1 A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero. We shall now SOLVE each term = 0 separately In other words, we are going to solve as many equations as there are terms in the product Any SOLUTION of term = 0 solves product = 0 as well.Solving a Single VARIABLE Equation: 4.2 Solve : 6x = 0 Divide both sides of the equation by 6: x = 0Solving a Single Variable Equation: 4.3 Solve : 3x-1 = 0 Add 1 to both sides of the equation : 3x = 1Divide both sides of the equation by 3: x = 1/3 = 0.333Two solutions were FOUND : x = 1/3 = 0.333 x = 0 |
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