1.

Divide 3000 into two parts such that the simple interest on the first part for 4 years at 8% per annum is equal to the simple interest on the second part for 2 years at 9% per annum. ​

Answer» <html><body><p><strong>Step-by-step explanation:</strong></p><p>Let the <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> <a href="https://interviewquestions.tuteehub.com/tag/part-596478" style="font-weight:bold;" target="_blank" title="Click to know more about PART">PART</a> be Rs. x. <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> part =(3000−x) ∴S.I. on x at 8% per annum for 4 years=</p><p>x×8×421</p><p>1005025</p><p> </p><p>=</p><p><a href="https://interviewquestions.tuteehub.com/tag/8x-340330" style="font-weight:bold;" target="_blank" title="Click to know more about 8X">8X</a></p><p>25</p><p> </p><p>S.I. on (3000−x) at <a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>% per annum =</p><p>(3000−x)×9×21</p><p>10050</p><p> </p><p> =</p><p>27000−9x</p><p>50</p><p> </p><p>∴</p><p>8x</p><p>25</p><p> </p><p>=</p><p>27000−9x</p><p>50</p><p> </p><p>=&gt;8x=</p><p>(27000−9x)×251</p><p>502</p><p> </p><p>=&gt;16x=27000−9x =&gt;16x+9x=27000 =&gt;x=</p><p>270001080</p><p>251</p><p> </p><p>=1080 ∴First part = Rs.1080 </p></body></html>


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