1.

dm^(3) of water contains 90 g of glucose. The mole fraction of glucose in the solution is

Answer»

0.33
0.66
0.5/56.05
0.5/55.55

Solution :`"Moles of WATER"="MASS"/"MOLAR mass"=1000/18=55.56`
Moles of GLUCOSE `="Mass"/"Molar mass"=90/180=0.5`
Mole fraction of glucose `= 0.5/(0.5 + 55.56)=0.5/56.06`


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