InterviewSolution
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Do the point (3,2),(-2,-3) and (2,3) from a triangle ? If so, name the type of triangle formed. |
Answer» QuestionDo the point (3,2),(-2,-3) and (2,3) from a triangle ? If so, name the type of triangle formed.GIVEN:Three POINTS (3,2) , (-2,-3) , (2,3) TO FIND:Do these points form a triangle?, If yes then which type of triangle is formed? SOLUTION:There are two ways of finding while these points are forming triangle or not. By PLOTTING the points in a graph By calculating the area of figure formed by these points. So, here we will do it by finding the area Using FORMULA to calculate area of triangle→ Area = 1/2 \mid∣ [ x_1x 1
( y_2y 2
- y_3y 3
) + x_2x 2
( y_3y 3
- y_1y 1
) + x_3x 3
( y_1y 1
- y_2y 2
) ] \mid∣ → Area = 1/2 | [ 3 ( -3 - (3) ) + (-2) ( 3 - 2 ) + 2 ( 2 - (-3) ) ] | → Area = 1/2 | [ -18 - 2 + 10 ] | → Area = 1/2 | [ -10 ] | → Area = 5 sq. units Since, the area of figure formed by three points is not zero, it means three points are forming a triangle. Now,Let us take A ( 3,2 ) , B ( -2,-3 ) , C ( 2,3 ) Then, Finding distances using distance formula Distance = √[ ( x₁ - x₂ )² + ( y₁ - y₂ )² ] → AB = √[ (3 - (-2))² + ( 2 - (-3))² ] → AB = √( 25 + 25 ) = √50 units → BC = √[ (-2 - 2)² + (-3 - 3)² ] → BC = √( 16 + 36 ) = √52 units → AC = √[ (3 - 2)² + (2 - 3)² ] → AC = √( 1 + 1 ) = √2 units Here, by Considering the lengths of sides of triangle we can conclude that, lengths of AB, BC, and AC are forming a Pythagorean triplet; BC² = AB² + AC² ( √52 )² = ( √50 )² + ( √2 )² It means these lines are forming a right angled triangle. |
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