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Doppler shift for the light of wavelength 6000 Å emitted from the sun is 0.04 Å.If radius of the sun is 7 xx 10^(8) m then time period of rotation of the sun will be : |
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Answer» 30 dyas `d lambda = (v)/(c) lambda = R.OMEGA ((lambda)/(c))` `omega = (2pi)/(T)` `THEREFORE R((2pi)/(T)).(lambda)/(c) = d lambda` `T = (R . 2 PI)/(d lambda).(lambda/c) = 25 days`. |
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