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Draw a labelled diagram of AC generator. Derive the expression for the instantaneous value of the emf induced in the coil. |
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Answer» Solution :Labelled diagrma of AC generator. Alternatively [Deduct `1//2` MARK, if diagram is not labelled] When the coil is rotated with constant ANGULAR speed `bar(omega)` the angle `theta` betwe the magnetic field and area vector of thecoil at instant, t is by `theta=bar(omega)t`. Therefore , magnetic FLUX `,(phi_(B))` at this instant is `phi_(B)=BA cos bar(omega)t` `:.` induced emf `e=-N(d phi_(B))/(dt)` `e=NBA bar(omega)sin bar(omega) t =e_(0)sin bar(omega)t` where `e_(0)=NBA bar(omega)` |
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