1.

Draw a labelled diagram of AC generator. Derive the expression for the instantaneous value of the emf induced in the coil.

Answer»

Solution :Labelled diagrma of AC generator.
Alternatively


[Deduct `1//2` MARK, if diagram is not labelled]
When the coil is rotated with constant ANGULAR speed `bar(omega)` the angle `theta` betwe the magnetic field and area vector of thecoil at instant, t is by `theta=bar(omega)t`.
Therefore , magnetic FLUX `,(phi_(B))` at this instant is
`phi_(B)=BA cos bar(omega)t`
`:.` induced emf `e=-N(d phi_(B))/(dt)`
`e=NBA bar(omega)sin bar(omega) t =e_(0)sin bar(omega)t`
where `e_(0)=NBA bar(omega)`


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