Draw aRough sketch of aof a quadrilateral PQRSTwo pairs of opposite si

1.	Draw aRough sketch of aof a quadrilateral PQRSTwo pairs of opposite sides.Two pairs of opposite angles.Two pairs of adjacent sideTwo pairs of adjacent angles
Answer» ANSWER: This IMPLIES that x2+2ax=4x−4a−13 or x2+2ax−4x+4a+13=0 or x2+(2a−4)x+(4a+13)=0 Since the equation has just ONE solution instead of the USUAL two distinct solutions, then the two solutions must be same i.e. discriminant = 0. Hence we get that (2a−4)2=4⋅1⋅(4a+13) or 4a2−16a+16=16a+52 or 4a2−32a−36=0 or a2−8a−9=0 or (a−9)(a+1)=0 So the values of a are −1 and 9.

Draw aRough sketch of aof a quadrilateral PQRSTwo pairs of opposite sides.Two pairs of opposite angles.Two pairs of adjacent sideTwo pairs of adjacent angles

Answer»

x2+2ax=4x−4a−13

x2+2ax−4x+4a+13=0

x2+(2a−4)x+(4a+13)=0

Since the equation has just ONE solution instead of the USUAL two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

4a2−16a+16=16a+52

4a2−32a−36=0

a2−8a−9=0

(a−9)(a+1)=0

So the values of a are −1 and 9.