1.

Draw logic diagrams for the Boolean expressions given below. (i)A . barB+barA . B=Y , (ii)(A+barB). (barA+B)=Y

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Solution :(i) The REQUIRED logic diagram for the given Boolean expression is given in FIGURE. Here the input B before applying to first AND GATE and input A before applying to second AND gate have been inverted. The output these gates are, THEREFORE, `AbarB` and `barAB` respectively. These outputs are FED to OR gate which gives `Y = AbarB+ barAB` as shown in figure.

(ii) The required logic diagram for the given Boolean expression is shown in figure. The input B to first OR gate and input A to second OR gate have been inverted, The output of these gates are, therefore, `A+barB` and `barA+B` as shown. These inputs when applied to AND gate give the required output.
`Y=(A+barB).(barA + B)`


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