InterviewSolution
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InterviewSolution
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Draw phasor diagram for the ac circuit comprising of a pure inductor. |
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Answer» Solution :`epsilon = epsilon_(0) SIN omega t` `epsilon -L (d i)/(d t) = 0` `(d i)/(d t) = (epsilon)/(L) = (epsilon_(0))/(L) sin omega t` `underset(0)overset(i)int (di)/(d t) d t = (epsilon_(0))/(L) underset(0)overset(i)int sin omega tdt` `i= -(epsilon_(0))/(omega L) cos omega t` `rArr i = - (epsilon_(0))/(X_(L)) sin (omega t - pi//2), sin C^(e)(X_(L) = omega L)` `rArr i = i_(0) sin(omega t - (pi)/(2))` where , `i_(0) = (-epsilon_(0))/(X_(L))` 
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