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Draw the graph of the equation 4x + 7y = 28 and tell the points where the line cuts x-axis and the y-axis |
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Answer» : • Point of intercept on x-axis is A(7 , 0) .• Point of intercept on y-axis is B(0 , 4) .Working rule : → Choose two or three points SATISFYING the given equation .→ Mark those points on the GRAPH PAPER .→ Join those points with scale .Solution : Here ,The given equation is : 4x + 7Y = 28 .• At x-axis , y-coordinate is zero .Thus , Putting y = 0 in the given equation ; We have ;=> 4x + 7•0 = 28 => 4x + 0 = 28 => 4x = 28 => x = 28/4 => x = 7 Hence , The graph of the given equation will cut the x-axis at the point A(7 , 0) .• At y-axis , x-coordinate is zero .Thus ,Putting x = 0 in the given equation ;We have ; => 4•0 + 7y = 28 => 0 + 7y = 28 => 7y = 28 => y = 28/7=> y = 4 Hence , The graph of the given equation will cut the y-axis at the point B(0 , 4) .To draw the graph : → Mark the points A(7 , 0) and B(0 , 4) on the graph paper .→ Join these points with the scale .Hence ,The graph is obtained .(For graph , PLEASE refer to the attachment.) |
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