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draw the graphs of equation 2 x - Y =1 and 3 X + 2 Y =12 determine the vertices of the Triangle formed by the triangle representing the equation and the x axis shade the triangular region so formed also find its area |
Answer» EXPLANATION.Draw Graph of the equation. ⇒ 2x - y = 1. - - - - - (1). ⇒ 3x + 2y = 12. - - - - - (2). As we know that, Form equation (1), we get. ⇒ 2x - y = 1. - - - - - (1). Put the value of X = 0 in the equation, we get. ⇒ 2(0) - y = 1. ⇒ - y = 1. ⇒ y = - 1. Their Co-ordinates = (0,-1). Put the value of y = 0 in the equation, we get. ⇒ 2x - (0) = 1. ⇒ 2x = 1. ⇒ x = 1/2. ⇒ x = 0.5. Their Co-ordinates = (0.5,0). From equation (2), we get. ⇒ 3x + 2y = 12. - - - - - (2). Put the value of x = 0 in the equation, we get. ⇒ 3(0) + 2y = 12. ⇒ 2y = 12. ⇒ y = 6. Their Co-ordinates = (0,6). Put the value of y = 0 in the equation, we get. ⇒ 3x + 2(0) = 12. ⇒ 3x = 12. ⇒ x = 4. Their Co-ordinates = (4,0). Both curves intersects at a point = (2,3). As we know that, ⇒ Area of triangle = 1/2 x Base x HEIGHT. ⇒ Height = 3 cm. ⇒ Base = 4 - 0.5 = 3.5 cm. Put the values in the equation, we get. Area of triangle = 1/2 x 3.5 x 3. Area of triangle = 5.25 SQ. units. |
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