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Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI |
Answer» Solution : This reaction follows `SN^(1)` MECHANISM because in this reaction the more stable carbocation is formed that is double bonded carbocation. THEREFORE, the given molecule reacts with HI to form ETHANOL and 1-iodo prop-1-ene. `CH_(3)-CH=CH-O-C_(2)H_(5) overset(HI//Delta)(RARR)underset(("1-iodo prop-1-ene"))(CH_(3)-CH=CH-I)+underset(("ethanol"))(C_(2)H_(5)OH)` |
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