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Draw the output signal C_(1) and C_(2) in the given combination of gates (Fig.) |
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Answer» SOLUTION :Here, In circuit, `C_(1)=bar(bar(barA.barB))=bar(bar(baAr)+bar(barB))=bar(A+B)` In circuit, `C_(2)=bar(barA+barB)=4bar(barA).bar(barB)=A.B` For the given SIGNALS shown in Fig. and , we have the following values for `A,B, C_(1)` and `C_(2)`. (i) For time 0TO`1s, A=1, B=0, C_(1)=0, C_(2)=0` (ii) For time `1s`to`2s, A=1, B=1, C_(1)=0, C_(2)=1` (iii) For time `2sto3s, A=0, B=1, C_(1)=0, C_(2)=0` (iv) For time `3sto4s, A=1, B=0, C_(1)=0, C_(2)=0` (v) For time `4sto5s, A=0, B=0, C_(1)=1, C_(2)=0`. The output signal `C_(1)` and `C_(2)` are shown in Fig. |
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