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Draw the structure of the semicarbazone of ethanal. |
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Answer» SOLUTION :Reaction OCCURS through the more nucleophilic `NH_(2)` (ATTACHED to NH) and not through `NH_(2)` attached CO group. Thus, `underset("Ethanol")(CH_(3)-CH=O)+underset("Semicarbozide")(H_(2)N NHCOCH_(2)) overset(pH" "3.5)to underset("ETHANAL semicarbazone")(CH_(3)-CH=N NHCOCH_(2))+H_(2)O` |
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