Saved Bookmarks
| 1. |
Draw the structures of the following :(i)H_(2)S_(2)O_(8)(ii) HClO_(4)(b)How would you account for the following :(i) NH_(3)is a stronger base than PH_(3).(ii) Sulphur has a greater tendency for catenation than oxygen.(iii) F_(2) is stronger oxidising agent than Cl_(2). |
Answer» Solution :(a)`H_(2)S_(2)O_(8)`(Peroxodisulphurc acid )![]() (ii) `HClO_(4)`(Perchloric acid) ![]() (ii)The property of catenation depends upon the ELEMENT - element bond. Since sulphur S-S bond STRENGTH is muchmore than O-O bond strength . Sosulphur has greater tendency for catenation than oxygen. (iii)Since the OXIDISING power of halogens decreases from `F_(2)` to `I_(2)`.Therefore `F_(2)` is the stronger oxidising agent than `Cl_(2)`due smaller size and absent ofd- orbital. |
|