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Drops of water fall at regular intervals from the rood of a building of height H=16m,the first drop striking the ground at the same moment as the fifth drop detaches from the rood.Find the distance between the successive drops. |
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Answer» Solution :Step-i:Time taken by the first Drop to touch the ground =`t=sqrt(2h)/(g)` For h=16m,t=`sqrt(2xx16)/(g)=4sqrt(2)/(g)` Time interval between two DROPS is `t_(int erval)=(1)/(n-1)t=(1)/(4)t=sqrt((2)/(g))` Where n=number of drops Step-ii DISTANCE between first and SECOND drops `=S_(1)-S_(2)=(1)/(2)"gt"_("int erval")^(2)[4^(2)-3^(2)]=7M` . Distance between second and third drops `=S_(2)-S_(3)=(1)/(2)"gt"_("interval")^(2)[3^(2)-2^(2)]=5m`. Distance between third and fourth drops `=S_(3)-S_(4)=(1)/(2)"gt"_("interval")^(2)[2^(2)-1^(2)]=3m` Distance between fourth and fifth drops. `=S_(4)-S_(5)=(1)/(2)"gt"_("interval")^(2)[1^(2)-0]=1M`. |
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