Due to a small magnet intensity at a distance `x` in the end on position is `9` Gauss. What will be the intensity at a distance `(x)/(2)` on broad side on position?A. `9` GaussB. `4` GaussC. `36` GaussD. `4.5` Gauss

Due to a small magnet intensity at a distance `x` in the end on positi

1.	Due to a small magnet intensity at a distance `x` in the end on position is `9` Gauss. What will be the intensity at a distance `(x)/(2)` on broad side on position?A. `9` GaussB. `4` GaussC. `36` GaussD. `4.5` Gauss
Answer» Correct Answer - C In C.G.S. `B_("axial")=9=(2M)/x^(3)` …(i) `B_("equaterial")=M/(x/2)^(3)=(8M)/x^(3)` …(ii) From equations (i) and (ii) `B_("equaterial")=36` Gauss

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Due to a small magnet intensity at a distance `x` in the end on position is `9` Gauss. What will be the intensity at a distance `(x)/(2)` on broad side on position?A. `9` GaussB. `4` GaussC. `36` GaussD. `4.5` Gauss

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