InterviewSolution
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InterviewSolution
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During a projectile motion if the maximum height equal the horizontal range, then the angle of projection with the horizontal is :A. `tan^(-1)(1)`B. `tan^(-1)(2)`C. `tan^(-1)(3)`D. `tan^(-1)(4)` |
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Answer» Correct Answer - d `H=(u^(2) sin^(2) theta)/(2g) and R=(u^(2) sin 2 theta)/g` Since `H=R(u^(2) sin^(2) theta)/(2g) =(u^(2)xx2sin theta cos theta)/g` or `tan theta=4 or theta=tan^(-1)(4)` |
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