1.

During an adiabatic compression of 2 moles of a gas, 100 of work was done. The change in the internal energy will be:

Answer»

50 J
`-100 J`
`-50 J`
100 J

Solution :According to first law of thermodynamics
`DQ =dU + DW`
For adiabatic process `dQ =0" "therefore dU =-dW`
As work is done on the gas `therefore dW =-100 J`.
`therefore dU =-(-100 J) =100 J`.
Thus, CORRECT choice is (d).


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