1.

During discharge of Dry cell , the gas liberated at the cathode is :

Answer»

`H_(2)`
`O_(2)`
`Cl_(2)`
`N_(2)`

SOLUTION :In dry cell , reduction take place at C cathode as -
` 2NH_(4)^(+) + 2e^(-) to 2 NH_(3) + H_(2)`


Discussion

No Comment Found

Related InterviewSolutions