1.

During electrolysis of 1 litre of aq. CuSO_4 , the P^(H) of the solution is changed from 5.0 to 4.3 . Then the number of faradays consumed in the process is (x xx 10^(-4)) , here , (x + y) = ?

Answer»


Solution :`(H_2O + CuSO_4) overset("electrolysis/2F")to CU+ (1)/(2)O_2 UARR + (2H^(oplus)+ SO_4^(-2))`
` 2F overset("PASSED ") to 2` moles of `H^(oplus)`
`Q to n xx 4 xx 10^(-5) , n = (Q xx 2)/(2F) = 4 xx 10^(-5) , Q = 4 xx 10^(-5) xxF`
` Q = x xx 10^(-4) xx F , (x + y) = (4+5) = 9`


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