1.

During electrolysis of a concentrated aqueous solution of NaCl , what is the product at anode ?

Answer»

`Na`
`Cl_(2)`
`O_(2)`
`H_(2)`.

Solution :`Cl_(2)`is produced as `Cl^(-)` IONS need voltage for OXIDATION to `Cl_(2)` than needed by `H_(2)O` for oxidation to `O_(2)` (This EXTRA voltage needed by `H_(2)O` is CALLED overvoltage) .


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