1.

During electrolysis of H_(2)O , the molar ratio of H_(2) and O_(2) formed is

Answer»

` 2 : 1`
`1 : 2`
`1 : 3`
`1 : 1`

SOLUTION :`H_(2)O to H_(2) + 1//2 O_(2)`
`THEREFORE` The ratio of `H_(2)` to `O_(2)`
`1 : 0.5therefore 2 : 1`


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