During electrolysis of NaOH – InterviewSolution

1.	During electrolysis of NaOH
Answer» `H_(2)` is liberarted at cathode `O_(2)` is liberated at cathode `H_(2)` is liberated at ANODE `O_(2)`is liberatedat anode. SOLUTION :During ELECTROLYSIS of NaOH (molten), `O_(2)` is liberated at anode. `4OH^(-)rarr2H_(2)O+O_(2)+4e^(-)`

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