1.

During the decomposition of H_2O_2 to given dioxygen , 48 g O_2 is formed per minute at certain point of time . The rate of formation of water at this point is .......

Answer»

`0.76 "MOL min"^(-1)`
`1.5 "mol min"^(-1)`
`2.25 "mol min"^(-1)`
`3.0 "mol min"^(-1)`

Solution :`H_2O_2rarrH_2O+1//2O_2`
RATE = `(-d[H_2O_2])/(dt)=(d[H_2O_2])/(dt)=(d[H_2O])/(dt)=(2D[O_2])/(dt)`
No. of MOLES of oxygen = `(48/32)=1.5mol`
Rate of FORMATION of oxygen `=2x1.5 `
`3 " mol min"^(-1)`


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