1.

During the fission of U-235, a large amount of energy of the order of 180 MeV is generated per nucleus fissioned. The amount of energy released by the fission of 0.235 g of U-235 is :

Answer»

`6.932xx10^(23)kJ`
`1.08xx10^(7)kJ`
`1.73xx10^(16)kJ`
`1.73xx10^(7)kJ`

Solution :No. of nuclei in 0.235 G of U-235
`=(6.02xx10^(23)xx0.235)/(235)`
`=6.02xx10^(20)` AMOUNT of energy released
`=6=02xx10^(20)xx180MeV`
`=6.02xx10^(20)xx180xx1.6xx10^(-16)kJ`
`=1.73xx10^(7)kJ`


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