During the working of the following cell `Pb-Hg(1M)|Pb^(2+)(aq)(0.1M)|` `|Pb^(2+)(aq)(0.1M)|Pb-Hg(0.5M)`A. `[Pb^(2+)]` decreases in cathodic half cellB. `[Pb^(2+)]` increases in anodic half cellC. `[Pb^(2+)]` increases in cathodic half cellD. Conc. Of lead amalgam increases in cathodic half cell whereas decreases in anodic half-cell

During the working of the following cell `Pb-Hg(1M)|Pb^(2+)(aq)(0.1M)|

1.	During the working of the following cell `Pb-Hg(1M)\|Pb^(2+)(aq)(0.1M)\|` `\|Pb^(2+)(aq)(0.1M)\|Pb-Hg(0.5M)`A. `[Pb^(2+)]` decreases in cathodic half cellB. `[Pb^(2+)]` increases in anodic half cellC. `[Pb^(2+)]` increases in cathodic half cellD. Conc. Of lead amalgam increases in cathodic half cell whereas decreases in anodic half-cell
Answer» Correct Answer - A During the working of cell, Pb is oxidized at anode and `Pb^(+2)` is reduced at cathode.

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