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`(dy)/(dx)` ज्ञात कीजिए| `log(logx)` |
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Answer» माना `y=log(logx)` `rArr" "(dy)/(dx)=(d)/(dx)log(logx)` `" "=(1)/(logx)(d)/(dx)(logx)` `" "=(1)/(xlogx)=(x logx)^(-1)` `rArr" "(d^(2)y)/(dx^(2))=(d)/(dx)(x log x)^(-1)` `" "=-1.(xlogx)^(-2)(d)/(dx)(xlogx)` `" "-([x.(1)/(x)+logx+logx(d)/(dx)x])/((x log x)^(2))` `" =-([x.(1)/(x)+logx])/((x log x)^(2))` `" "=-((1+logx))/((xlogx)^(2))` |
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