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`(dy)/(dx)` ज्ञात कीजिए|`sin^(3)x+cos^(6)x` |
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Answer» माना `y=sin^(3)x+cos^(6)x` `rArr" "(dy)/(dx)=(d)/(dx)(sin^(3)x+cos^(6)x)` `" "=(d)/(dx)(sinx)^(3)+(d)/(dx)(cosx)^(6)` `" "=3(sinx)^(2)(d)/(dx)(sinx)+6(cosx)^(5)(d)/(dx)(cosx)` `" "=3sin^(2)xcosx-6cos^(5)xsinx` `" "=3sinx cos (sinx-2cos^(4)x)` |
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