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`(dy)/(dx)` ज्ञात कीजिए| `x =a cos theta, y = b cos theta` |
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Answer» `x=acos theta" "y=b cos theta` `rArr" "(d x)/(d theta)=- a sin theta" "rArr (dy)/(d theta)- b sin theta` `therefore " "(dy)/(dx)=(dy//d theta)/( dx// d theta)=(-b sin theta)/(-a sin theta)=(b)/(a)` |
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