`(dy)/(dx)` ज्ञात कीजिए : `y=sin^(-1)((2x)/(1+x^(2

1.	`(dy)/(dx)` ज्ञात कीजिए : `y=sin^(-1)((2x)/(1+x^(2)))`
Answer» `y=sin^(-1)((2x)/(1+x^(2)))" "{:("माना "x=tan theta),(rArr theta= tan^(-1)x):}` `rArr" "y=sin^(-1)((2 tan theta)/(1+tan^(2) theta))` `=sin^(-1)((2 tan theta)/(sec^(2) theta))=sin^(-1)(2 sin theta cos theta)` `=sin^(-1)(sin 2 theta)= 2 theta = 2 tan^(-1)x`

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